WebIf A`=tan6^0tan42^0 and B=cot66^0cot78^0` , then. class-11; trignometric-ratio-and-identities; Share It On Web10 Jan 2024 · Explanation: x = tan81 + tan9 −(tan63+ tan27) = cot9 +tan9 −(cot27 + tan27) = (cos9)2 + (sin9)2 sin9 ⋅ cos9 − (cos27)2 +(sin27)2 sin27⋅ cos27. = 1 sin9 ⋅ cos9 − 1 sin27 ⋅ cos27. = 2 sin18 − 2 sin54. = 2 ⋅ sin54 −sin18 sin54 ⋅ sin18. = 4cos36⋅ sin18 cos36 ⋅ sin18.
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Web9 Aug 2024 · a=tan6 tan42 b=cot66 cot78 can be written as tan24 tan12 bec cot (90-t)=tant; tanA tanB = tanC tanD if A+B=C+D; or A+B =C-D or A-B=C+D or A-B=C-D; as 42-6=24+12; … WebA=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan (60-x)tanxtan (60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54°... (1) for x=6° we get … cloud city ice cream portland oregon
[Resuelta] precálculo-algebra Si $A = \tan6^{\circ}
WebMy trigonometric problem is: If A = tan6 ∘ tan42 ∘ B = cot 66 ∘ cot78 ∘ find the relation between A and B. Working : B = cot66 ∘ cot78 ∘ = 1 − tan24 ∘ + tan18 ∘ tan42 ∘ A = tan6 ∘ … Web2 no of correct responsetotal no of correct options 36 If 2 3 cos cos cos A B B from PIANO Bachelor at Royal Scottish Academy of Music and Drama WebA=tan6°tan42° and B=cot66°cot78° A/B=tan6°tan42°tan66°tan78° Using tan(60-x)tanxtan(60+x)=tan3x for x=18° we get tan42°tan18°tan78°=tan54°...(1) for x=6° we get tan54°tan6°tan66°=tan18°...(2) Eliminating tan54°between (1) and (2) we get tan6°tan42°tan66°tan78°=1 Hence A/B=1. A=B Regards cloud city ks